x^2+54x+629=0

Solution for x^2+54x+629=0 equation:

x^2+54x+629=0

a = 1; b = 54; c = +629;
Δ = b2-4ac
Δ = 542-4·1·629
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-20}{2*1}=\frac{-74}{2}
=-37
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+20}{2*1}=\frac{-34}{2}
=-17
$